![]() ![]() Once all four segments of League and Nation. The first time read this challenge, you’ll get. *In the example below, Ayrton, a LB from the Russian League was used in place of Filipe Anderson (Serie A), and Luiz Felipe was used over Pablo to counteract the opposite leagues, due to loyalty bonuses. The Fiendish SBC is the third segment in the League and Nation Hybrid group, to which we already have solutions for Advanced and Puzzle Master. 9:33 AM -08:00 UTC FIFA 22: All Active SBCs & Cheapest Solutions (January 4th) Will you be completing the challenges By Tom Young Squad Building Challenges are one of the best ways to get your hands on the biggest and best cards that FIFA 22 has to offer. The following is a working solution for the Fiendish SBC in FIFA 23. The total cost for the FIFA 22 First XI SBC is roughly 24,000 coins, although depending on who you've already packed, this can be decreased drastically. Striker - Alex Teixeria (77 Rated, Super Lig, 1,500 Coins) The Fiendish SBC is the third segment in the League and Nation Hybrid group, to which we already have solutions for Advanced and Puzzle Master.Right Midfield - Pedrinho (75 Rated, Ukrayina Liha, 1,500 Coins).Centre Midfield - Oscar (82 Rated, Chinese Super League, 5,000 Coins).Centre Midfield - Paulinho (83 Rated, MBS Pro League, 2,000 Coins).Left Midfield - Felipe Anderson (78 Rated, Serie A, 3,800 Coins).Defensive Midfield - Bruno Guimaraes (79 Rated, Ligue 1, 850 Coins).Right Back - Emerson (79 Rated, Premier League, 2,800 Coins). ![]() Centre Back - Pablo (77 Rated, League of Russia, 3,800 Coins) There are three squad building challenges (SBC) in FIFA 22 Ultimate Team that players can complete right from the startand the League and Nation Hybrid SBC is one of them.Centre Back - Gabriel Paulista (82 Rated, Liga Santander, 1,200 Coins).Left Back - Paulo Otavio (76 Rated, Bundesliga, 3,000 Coins) Updated list featuring all FIFA 22 Squad Building Challenges, including individual and group SBC rewards, start and end dates.Getting the players to the correct position is the first task. ![]()
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